This post contains a total of 15+ Hand-Picked Python Armstrong Number Checker & Finder Program Examples with Source Code. All the Armstrong Number Checker & Finder programs are made using Python Programming Language.
You can use the source code of these programs for educational purpose with credits to the original owner.
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1. By Mert YazΔ±cΔ±
Made by Mert YazΔ±cΔ±. Python program to check if a number is Armstrong or not. ( Source )
371 371 is armstrong number. 3**3 + 7**3 + 1**3 = 27 + 343 + 1 = 371 = 371
i = input()
sum = 0
for a in i:
sum += int(a)**len(i)
print(i + " is"+ int(not sum==int(i))*" not"+" armstrong number.")
print((" + ".join(i for i in (a + "**" + str(len(i)) for a in i)) + " =\n" + " + ".join(i for i in (str(int(a)**len(i)) for a in i)) + " =\n" + str(sum)).strip() + (' =' + '/='*(sum!=int(i))), i)2. By Infant Raj
Made by Infant Raj. Program in python to find all the Armstrong numbers from 0 to 1000. ( Source )
0 Is an Armstrong Number 1 Is an Armstrong Number 2 Is an Armstrong Number 3 Is an Armstrong Number 4 Is an Armstrong Number 5 Is an Armstrong Number 6 Is an Armstrong Number 7 Is an Armstrong Number 8 Is an Armstrong Number 9 Is an Armstrong Number 153 Is an Armstrong Number 370 Is an Armstrong Number 371 Is an Armstrong Number 407 Is an Armstrong Number
#looping the numbers from 0 to 1000
for i in range(0,1000):
if int(i) < 1000 :
# length of the number
new = len(str(i))
#running total
total = 0
#finding the cube of each digit
newNum = i
while int(newNum) > 0:
temp = int(newNum) % 10
total += temp ** new
(newNum) //= 10
#if you want to filter the single digit numbers
#singleDigit = [2,3,4,5,6,7,8,9]
#output the result
if i == total: #and i not in singleDigit:
print(i, "Is an Armstrong Number")
"""
else:
print(i, "Is NOT")
""" 3. By πβ’β¦ββ£βπ
Made by πβ’β¦ββ£βπ. ( Source )
Your entered number:370 It is armstrong
num=int(input("Your entered number:"))
print(num)
sum=0
temp=num
while temp>0:
digit=temp%10
sum+=digit**3
temp//=10
if num==sum:
print("It is armstrong")
else:
print("")4. By David Ashton
Made by David Ashton. ( Source )
34 34 is not an Armstrong Number.
def is_an(n):
"""Check for Armstrong Number."""
return int(n) == sum(int(d)**3 for d in n)
n = input() or "407"
print(f"{n} is{' ' if is_an(n) else ' not '}an Armstrong Number.")5. By Python World
Made by Python World. ( Source )
Enter a no: 153 153 is armstrong no
num =int(input("Enter a no: "))
#initialize
sum =0
temp= num
while temp>0:
digit =temp%10
sum+=digit**3
temp//= 10
if num == sum:
print (num,"is armstrong no")
else:
print(num,"is not armstrong no")6. By SΓ’Γ±tΓ΄sh
Made by SΓ’Γ±tΓ΄sh. ( Source )
45 not armstrong number
x = input();sum=0
for i in range(len(x)):
y=int(x[i])**3
sum+=y
print("Armstrong Number"if int(x)==sum else "not armstrong number")
7. By ApidBoy
Made by ApidBoy. This Program Simply Tells You That Whether A Number Is An Armstrong Or Not. ( Source )
345 No, 345 Is Not An Armstrong Number
#Taking Input From User In Integral Form
number = int(input())
#Defining A Variable And Assigning Value "0" To It
x = 0
#Conserving The Value Of Variable "number" In Variable "y"
y = number
#Creating A While Loop
while number>0:
#To Get The Number In Tense, Hundreath, etc Places, Using Modulus To Get Remainder
z = number%10
#Getting The Cubes Of The Number Modded By 10 Above
x = x+z*z*z
#Performing Floor Division To Get Exact Value Of The Number
number = number//10
#If The Number Conserved Above Is Equal To The Number Present In Variable "y" Then, The Number Will Be An Armstrong Number
if y==x:
print("Yes,",y,"Is An Armstrong Number")
#And If Not Then It Will Not Be An Armstrong Number
else:
print("No,",y,"Is Not An Armstrong Number")
#Code Ends....8. By π Prometheus πΈπ¬
Made by π Prometheus πΈπ¬. ( Source )
370 Armstrong number!
a=int(input());print("Armstrong number!") if sum(list(map(lambda x:int(x)**3,list(str(a)))))==a else print("Not an Armstrong number!")9. By scientist
Made by scientist. Simple Armstrong number checker python program. ( Source )
==##Finding Whether Entered Number##== ==## is Armstrong Number or Not ##== Enter a three digit number: 234 ""Calculation"" Hundreds digit is 2.0 Its cube is 8.0 Tens digit is 3.0 Its cube is 27.0 Ones digit is 4 Its cube is 64 Your entered three digit number 234 is not an Armstrong number.
print ("==##Finding Whether Entered Number##==\n==## is Armstrong Number or Not ##==")
num=int(input("Enter a three digit number: "))
a=num%100
b=a%10
h_dig=(num-a)/100
t_dig=(a-b)/10
o_dig=b
print(num)
print("\n \"\"Calculation\"\"")
print("\n Hundreds digit is ", h_dig)
print(" Its cube is ",(h_dig)**3)
print("\n Tens digit is ", t_dig)
print(" Its cube is ",(t_dig)**3)
print("\n Ones digit is ", o_dig)
print(" Its cube is ",(o_dig)**3)
if (h_dig)**3 + (t_dig)**3 + (o_dig)**3 == num :
print("\n Your entered three digit number", num, " is an Armstrong number.")
else :
print("\n Your entered three digit number", num, " is not an Armstrong number.")
10. By David Ashton
Another Armstrong checker program by David Ashton to get all the Armstrong number in a given range. ( Source )
Armstrong Numbers to 2222 = 1, 153, 370, 371, 407
def is_an(n):
'''Check for Armstrong Number.'''
return int(n) == sum(int(d)**3 for d in n)
n = input() or "500"
print(f"Armstrong Numbers to {n} = ", end="")
print(*[i for i in range(1, int(n) + 1) if is_an(str(i))], sep=", ")11. By Ben
Made by Ben. ( Source )
Give a number: 407 The number 407 is a Armstrong number
number = str(input("Give a number: "))
armstrong = int(number)
sum = 0
for i in number:
sum += int(i) ** 3
if sum == armstrong:
print("The number " + str(armstrong ) +" is a Armstrong number")12. By David
Made by David. ( Source )
234 is not an Armstrong Number because: number of digits = 3 2^3 + 3^3 + 4^3 = 99 Armstrong Numbers to 234 = 1, 2, 3, 4, 5, 6, 7, 8, 9, 153
def is_an(n):
'''Check for Armstrong Number.'''
global digits
global total
return int(n) == (
total := sum(int(c)**(digits := len(n))
for c in n)
)
# more readable is:
# digits = len(n)
# total = sum(int(c)**digits for c in n)
# return int(n) == total
n = input() or "548834"
print(f"{n} is{' ' if is_an(n) else ' not '}an Armstrong Number because:")
print("number of digits =", digits)
for c in n[:digits - 1]:
print(f"{c}^{digits} + ", end="")
print(f"{n[-1:]}^{digits} = {total}")
print()
print(f"Armstrong Numbers to {n} = ", end="")
print(*(i for i in range(1, int(n)+1) if is_an(str(i))), sep=", ")13. By Tomiwa Joseph
Made by Tomiwa Joseph. Simple python program to find if a number is Armstrong or not, the program also prints all the Armstrong numbers that exist to that range. ( Source )
Is 307 an Armstrong number? False How? π€ Each element in 307 raised to the power of 3 is [27, 0, 343] Addition of each element raised to power is 370 Is 370 equal to 307 ? False Bonus challenge All the Abundant numbers within the given range 0 to 307 are: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 153]
def armstrong(number):
#convert each element in the input to an integer and raise it to the power of the length
raised = [int(i)**len(number) for i in number]
#add the numbers
addition = sum(raised)
#compare the addition to the number
return addition == int(number)
#enter your number or just press submit. The default number will be used
your_number = input() or '370'
print("Is",your_number,"an Armstrong number?\t",armstrong(your_number))
#Explanation variables
raised = [int(i)**len(your_number) for i in your_number]
print("\nHow? π€")
print("Each element in",your_number,"raised to the power of",len(your_number),"is",raised)
print("Addition of each element raised to power is",sum(raised))
print("\nIs",sum(raised),"equal to",int(your_number),"?\t",sum(raised) == int(your_number))
print("\n\nBonus challenge")
print("All the Abundant numbers within the given range 0 to",your_number,"are:\n")
#iterate through the range and for each element try it with the abundant function, if it returns True, add to the list, else, look awayπ
print([i for i in range(int(your_number)+1) if armstrong(str(i))])
print("\nBonus - Two-liner for an interested somebodyπ₯")
print("""\ndef armstrong(number):
return sum([int(i)**len(number) for i in number]) == int(number)""")
print("\n\nHappy coding ππ")
print("Do upvote if you like π·π€")14. By Janusz Bujak π΅π± πΊπ¦
Made by Janusz Bujak π΅π± πΊπ¦. ( Source )
407 407 is the Armstrong number. 233168
x = input() or '407' # 4Β³+0Β³+7Β³
y = sum(int(c)**len(x) for c in x)
print(x, 'is' if int(x)==y else 'is not', 'the Armstrong number.')
# Project Euler 1
print(sum([x for x in range(1000) if x%3==0 or x%5==0]))15. By F1
Made by F1. Prints all the Armstrong numbers in a given range. ( Source )
999 0 1 2 3 4 5 6 7 8 9 153 370 371 407
nums = []
def armstrong(x):
sum = 0
for i in str(x):
sum += int(i)**len(str(x))
if sum == x:
nums.append(x)
for i in range(int(input())):
armstrong(i)
for i in nums:
print(i)16. By Samarth
Made by Samarth. ( Source )
777 The Number 777 Is Not An Armstrong Number!
n = int(input())
a = list(map(int,str(n)))
b = list(map(lambda x:x**3,a))
if (sum(b)==n):
print("The Number",n,"Is An Armstrong Number!")
else:
print("The Number",n,"Is Not An Armstrong Number!")