This post contains a total of 8+ C Password Validator Program Examples with Source Code. All these programs to Validate Passwords are made using C Language.
You can use the source code of these examples with credits to the original owner.
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C Password Validator Program Examples
1. By Dark
Made by Dark. Simple Password validator Program. Source
Password is [email protected] Password is valid
#include <stdio.h>
#include<string.h>
int main() {
char s[10];
int sy=0,cap=0,num=0,i;
scanf("%s",s);
printf("Password is %s\n",s);
if(strlen(s)>5 && strlen(s)<10)
{
for(i=0;i<strlen(s);i++)
{
if(s[i]>65 && s[i]<91)
cap++;
else if(s[i]>48 && s[i]<57)
sy++;
else if(s[i]<97 || s[i]>123)
num++;
}
if(sy==0 || cap==0 || num==0){
printf("A strong password must be between 5-10 charcters and must contain atleast 1 or more symbols,capital letters,numbers");}
else
printf("Password is valid");
}
else
printf("Password is not between 5-10 characters");
return 0;
}2. By Aung Thiha
Made by Aung Thiha. C program to validate a password and test its strength. Source
[email protected] Cool!!!You entered the strong password.
#include <stdio.h> //making a in/out file
#include <string.h> //string libraby
int main( ){ // main function
int l=5,h=15,v= 1; //declaring variable
char n[10] = "0123456789" ;
char c[25] = "@#*¿$£€?|%^`´°•\:<>~_&/+-×";/*
_____________________________________
| read this two lines. you can only|
| add from those except of letters. |
-------------------------------------
*/char password[h+1];
gets(password);
if((strlen(password)>h)||(strlen(password)<l)){
v=0; }/*
_______________________________________
| strlen is used detect the string's |
| lengths.Is it <5 or >15 |
---------------------------------------
*/char *temp = password;
if (strpbrk(temp,n) == NULL){
v = 0;}
temp = password;
if (strpbrk(temp,c) == NULL){
v = 0;}/*
_____________________________________________
| strpbrk() is used to find the | | first character of first string and matches |
| it to any character of second string.It | | returns NULL, if no matches are found | | otherwise, it returns a pointer to the | | character of first string that matches to |
| the character of second string. |
---------------------------------------------
*/for(int i=0; password[i] != '\0'; i++){
if(password[i] == ' '){
v = 0;
break;}}
(v)? printf("Cool!!!You entered the strong password. I hope your password would be safe.")
: printf("Oops!!!I guess, your password is weak or invalid.\n\nYou should type\n1. at least 5 words.\n2. less than 15 words.\n3. at least 1 or 2 special characters.\n4. at least 1 number.\n\nexample : \t\t\tthiha#1122");/*
___________________________________________
| (v) ? statement : statment |
| is ternary operator. it is like with |
| 'if' condition operator...if(v) condition|
| is true statement is work. else condition|
| is wrong, statement won't work. |
-------------------------------------------
*/return 0;}3. By Rabs
Made by Rabs. Source
[email protected]@99 Strong
#include <stdio.h>
int main() {
char pass[20];
char str1[]="Strong";
char str2[]="Weak";
int length=0,num=0,special=0,i=0;
scanf("%s",pass);
length=strlen(pass);
while(pass[i] != '\0')
{
if(length>=7)
{
if(pass[i]>='0' && pass[i]<='9')
{
num++;
}
if(pass[i]=='!' || pass[i]=='@' || pass[i]=='#' || pass[i]=='$' || pass[i]=='%' || pass[i]=='*'|| pass[i]=='&')
{
special++;
}
}
++i;
}
if(num>=2 && special>=2)
{
printf("%s",str1);
}
else{
printf("%s",str2);
}
}4. By Vikash Karma
Made by Vikash Karma. Source
[email protected] True
#include<stdio.h>
#include<string.h>
int main(){
int len,num,spe,space;
int i;
char s[15];
num=spe=space=0;
gets(s);
len=strlen(s);
if(len>10||len<5)
printf("False\n");
else{
for(i=0;s[i];i++){
if(s[i]>=48&&s[i]<=57)
num++;
else if(s[i] ==32)
space++;
else if(!((s[i]>=48&&s[i]<=57)|| (s[i] ==32)||(s[i]>=65&&s[i]<=90)||(s[i]>=97&&s[i]<=122)))
spe++;
}}
if(num!=0&&space==0&&spe!=0)
printf("True\n");
else
printf("False\n");
return 0;
}5. By zhoolf
Made by zhoolf. Advanced Password validator Program. Source
[email protected] True
#include <stdio.h>
#include <string.h>
#define MIN_LEN 6
#define MAX_LEN 30
#define DIGITS "0123456789"
#define SPECIAL_CHARS "&[email protected]%#$/-!^<>_()*-~?"
unsigned int isValid = 1;
int main()
{
char input[MAX_LEN+1];
gets(input);
// check minimum and maximum length
if ((strlen(input) < MIN_LEN) || (strlen(input) > MAX_LEN))
isValid = 0;
char *temp = input;
// check if password contain at least one number
if (strpbrk(temp, DIGITS) == NULL)
isValid = 0;
temp = input;
// check if password contain at least one special char
if (strpbrk(temp, SPECIAL_CHARS) == NULL)
isValid = 0;
// check if password contain spaces
int i;
for (i=0; input[i] != '\0'; i++) {
if (input[i] == ' ') {
isValid = 0;
break;
}
}
(isValid) ? printf("true") : printf("false");
return 0;
}6. By Ajai
Made by Ajai. Source
****Password validator**** Enter Your password: 12abc Weak
#include<stdio.h>
int main()
{
int i, count=0, count_num = 0, count_sc= 0;
char str[100], ch;
printf("****Password validator****\n\nEnter Your password: ");
gets(str);
for(i=0; str[i]!='\0'; i++)
{
count++;
}
if(count <= 7 )
{
printf("Weak"); //if password has less than 7 characters it is weak
return 0;
}
else
{ for(i=0; str[i] != '\0'; i++)
{
if (str[i] >= '0' && str[i] <='9')
++count_num;
}
if(count_num < 2) //if password has less than 2 numbers it is weak
{
printf("Weak");
return 0;
}
else
for(i=0; str[i] != '\0'; i++) //checking for special characers [email protected]#$%&*
{
if (str[i] == '!' || str[i] == '@' ||str[i] == '#' ||str[i] == '$' ||str[i] == '%' ||str[i] == '*' ||str[i] == '&')
++count_sc ;
}
if(count_sc < 2)
{
printf("Weak"); //if password has less than 2 special characters it is weak
return 0;
}
else printf("Strong");
}
return 0;
}7. By HonFu
Made by HonFu. Source
Your input: qwerty Your password needs at least one digit and one special character!
#include <stdio.h>
int is_valid_pw(char *pw) {
int special=0, digit=0;
for(int i=0; pw[i]!='\0'; ++i) {
if (pw[i+1]=='\0'&&i<4) {
printf("Your password is "
"too short (<5)!\n");
return 0;
}
if (i>9) {
printf("Your password is "
"too long (>10)!\n");
return 0;
}
if (pw[i]<'!'||pw[i]>'~'||pw[i]=='\\') {
printf("Please use only visible "
"ASCII (except \\)!\n");
return 0;
}
if (pw[i]>='0'&&pw[i]<='9'&&!digit)
++digit;
else if (((pw[i]>=':'&&pw[i]<='@')
|| (pw[i]>='['&&pw[i]<=96)
|| (pw[i]>='{'&&pw[i])
|| pw[i]<='/')
&& !special)
++special;
}
if(!digit||!special) {
printf("Your password needs at least "
"one digit and one "
"special character!\n");
return 0;
}
return 1;
}
int main() {
char str[101];
printf("Your input: ");
scanf("%[^\n]", str);
printf("%s\n\n", str);
if(is_valid_pw(str))
printf("Valid!\n");
return 0;
}8. By Endeavourer
Made by Endeavourer. Source
w2w2 Weak Password!!
#include <stdio.h>
#include <string.h>
int main() {
char str[30];
int i,a=0,b=0,c=0;
scanf("%s",str);
for(i=0;str[i]!='\0';){
if((str[i]>='0')&&(str[i]<='9')){
a++;
i++;
}
else if((str[i]>='!')&&(str[i]<='/')){
b++;
i++;
}
else if(str[i]==' '){
c++;
i++;
}
else {
i++;
}
}
//here you can do little modification 😉
if((strlen(str)>=5)&&(strlen(str)<11)&&(a>=1)&&(b>=1)&&(c==0))
printf ("Strong Password!!");
else
printf ("Weak Password!!");
return 0;
}9. By Miquel Andreu Fuster Sancho
Made by Miquel Andreu Fuster Sancho. Source
aaa: 0 aaabbbcccddd: 0 aaabbb: 0 aaa bbb: 0 aaa0bbb: 0 [email protected]: 0 aaa0!bbb: 1
#include <stdio.h>
#include <string.h>
#include <ctype.h>
#include <stdbool.h>
bool validator(char *password) {
size_t str_len = strlen(password);
bool has_letters = false;
bool has_numbers = false;
bool has_symbols = false;
if(str_len < 5 || str_len > 10)
return false;
for(int i=0; i<str_len; ++i) {
if(isalpha(password[i]))
has_letters = true;
else if(isdigit(password[i]))
has_numbers = true;
else if(isgraph(password[i]))
has_symbols = true;
else // has spaces or non graphic chars
return false;
}
return has_letters && has_numbers && has_symbols;
}
int main() {
char *passwords[] = {"aaa", "aaabbbcccddd", "aaabbb", "aaa bbb", "aaa0bbb", "[email protected]", "aaa0!bbb"};
for(int i = 0; i < sizeof(passwords)/sizeof(passwords[0]); ++i)
printf("%s: %d\n", passwords[i], validator(passwords[i]));
}